ARRANGE  Arranging Amplifiers
Scientists at the TIFR, Mumbai, are doing some cutting edge research on the Propagation of Signals. A young researcher comes up with a method of progressively amplifying signals, as they progress along a path. The method involves the placing of Amplifiers at regular distances along the line. Each amplifier is loaded with a number a(i), which is called its amplification factor. The method of amplification is simple: an amplifier which recieves a signal of strength X, and has Y loaded in it, results in a signal of strength Y^X [ Y to the power X]. In course of his research, the young scientist tries to find out, that given a set of n amplifiers loaded with a(0), a(1), a(2), ...., a(n1), which particular permutation of these amplifiers, when placed at successive nodes, with the initial node given a signal of strength 1, produces the strongest output signal.
this is better illustrated by the following example : 5 6 4
4^(5^(6^1)) is the strength of the strongest signal, which is generated by putting amplifier loaded with 6 in first place, 5 in second place and 4 in third place.
Given a list of integers specifying the set of amplifiers at hand, you must find out the order in which they must be placed, to get the highest signal strength. In case their exist multiple permutations with same output, you should print the one which has bigger amplifiers first.
Input
First line of input contains T, the number of test cases. For each test case first line contains a number ni, which is equal to the number of amplifiers available. Next line contains n integers, separated by spaces which denote the values with which the amplifiers are loaded.
Output
Output contains T lines, one for each test case. Each line contains ni integers, denoting the order in which the amplifiers should be kept such that the result is strongest.
Example
Input: 2 3 5 6 4 2 2 3 Output: 6 5 4 2 3
Constraints and Limits
T ≤ 20, Ni ≤ 10^5.
Each amplifier will be loaded with a positive integer p, 0 < p ≤ 10^9.
No two amplifier > 1 shall be loaded with the same integer.
hide comments
shivanchal:
20210805 16:47:56
In exceptional cases in which we have only one 3 and 2s then it is getting accepted on wrong answers


immortal2211:
20210726 07:27:07
just read some article about x^y (relation) y^x 

evernox666:
20210708 19:32:24
TLE in java 

sinhadipti:
20210708 06:25:23
consider the cases 1, 2 and 3 

aadiiii:
20210704 16:46:17
AC in one go after reading some comments, make sure to check the test cases involving 2 and 3. :) 

anurag129:
20210627 05:46:47
This ide is just shit


fa1k0n:
20210617 12:51:46
About > 4 3 2 & 4 2 3


kha_02:
20210610 10:21:39
how to see the input data for our wrong answer 

terminator0309:
20210608 12:19:16
@dhruv_walia no repeatition allowed except for one


dhruv_walia:
20210607 17:12:41
For the test case 2 2 3 the correct output should be 2 3 2 but my solution got accepted with answer 3 2 2.

Added by:  Ajay Somani 
Date:  20080204 
Time limit:  1s 
Source limit:  50000B 
Memory limit:  1536MB 
Cluster:  Cube (Intel G860) 
Languages:  All except: ERL JSRHINO NODEJS PERL6 VB.NET 
Resource:  CodeCraft 08 Anshuman Singh 